A uniform magnetic field of induction `B` is confined to a cyclindrical region of radius `R`. The magnetic field is increasing at a constant rate of `dB//dt` (tesla`//` second). A charge `e` of mass `m`, placed at the point `P` on the periphery of the fixed experiences an acceleration :

Options

A. `1/2 (eR)/m(dB)/(dt)` toward left
B. `1/2 (eR)/m(dB)/(dt)` toward right
C. `(eR)/m(dB)/(dt)` toward left
D. zero

Answer

A

Explanation

`int vecE.d vecl=(dphi)/(dt)=A(dB)/(dt)`
`veca=-(qvecE)/m` . Direction of induced field can dtermined from Lenz.s law