Home
Class 12
PHYSICS
A straight solenoid of length 1 m has 50...

A straight solenoid of length `1 m` has `5000` turns in the primary and `200` turns in the secondary coil. If the area of cross section is `4 cm^(2)`, the mutual inductance will be

A

503 H

B

503 mH

C

`503 mu H`

D

5.03 H

Text Solution

Verified by Experts

The correct Answer is:
C

`M=(mu_0N_1N_2A)/(l)` a here l=1m =`503 xx10^(-6)H`
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION

    NARAYNA|Exercise EXERCISE-3|24 Videos
  • ELECTROMAGNETIC INDUCTION

    NARAYNA|Exercise EXERCISE-4|16 Videos
  • ELECTROMAGNETIC INDUCTION

    NARAYNA|Exercise EXERCISE-2 (C.W)|22 Videos
  • ELECTRO MAGNETIC WAVES

    NARAYNA|Exercise LEVEL-II(H.W)|14 Videos
  • ELECTROMAGNETIC WAVES

    NARAYNA|Exercise EXERCISE -4|15 Videos

Similar Questions

Explore conceptually related problems

A straight solenoid of length 1 m has 5000 turns in the primary and 200 turns in the secondary. If the area of cross section is 4 cm^(2) , the mutual inductance will be

A straight solenoid of length 1m has 5000 turns in the primary and 200 turns in the secondary.If the area of cross-section is 4cm^(2) ,the mutual inductance will be

A straight solenoid has 50 turns per cm in primary and total 200 turns in the secondary. The area of cross section of the solenoids is 4cm^2 . Calculate the mutual inductance. Primary is tightly kept in side the secondary.

If number of turns in primary and secondary coils is increased to two times each, the mutual inductance

A 100% efficient transformer has 100 turns in the primary and 25 turns in its secondary coil. Of the current in the secondary coil is 4 amp, then the current in the primary coil is

When the number of turns and the length of the solenoid are doubled keeping the area of cross-section same, the inductance

A transformer has 1500 turns in the primary coil and 1125 turns in the secondary coil. If a voltage of 200V is applied across the primary coil , then the voltage in the secondary coil is :

A solenoid is of length 50 cm and has a radius of 2cm . It has 500 turns. Around its central section a coil of 50 turns is wound. Calculate the mutual inductance of the system.

NARAYNA-ELECTROMAGNETIC INDUCTION-EXERCISE-2 (H.W)
  1. A coil of 30 turns of wire each of 10 cm^(2) area is placed with its p...

    Text Solution

    |

  2. A square coil of side 0.5 m has movable sides. It si placed such that ...

    Text Solution

    |

  3. A uniform magnetic field existsin region given by vec(B) = 3 hat(i) + ...

    Text Solution

    |

  4. Two identical conducting rings A and B of radius R are rolling over a ...

    Text Solution

    |

  5. A flexible wire loop in the shape of a circle has a radius that grows ...

    Text Solution

    |

  6. A rectangle loop with a sliding connector of length l=1.0 m is situate...

    Text Solution

    |

  7. A straight rod of length l si rotating about axis passing through O is...

    Text Solution

    |

  8. A rod of length 10 cm made up of conducting and non-conducting materia...

    Text Solution

    |

  9. A triangular wire frame (each side =2m) is placed in a region of time ...

    Text Solution

    |

  10. A uniform magnetic field of induction B is confined to a cyclindrical ...

    Text Solution

    |

  11. The e.m.f. induced in a secondary coil is 20000 V when the current bre...

    Text Solution

    |

  12. A small square loop of wire of side l is placed inside a large square ...

    Text Solution

    |

  13. A straight solenoid of length 1 m has 5000 turns in the primary and 20...

    Text Solution

    |

  14. Two coaxial circular loops of radius 0.5 m and 5 xx 10^(-2)m are separ...

    Text Solution

    |

  15. The mutual inductance between the rectangular loop and the long straig...

    Text Solution

    |

  16. An infinite long straight conducting cylinderical shell of radius a is...

    Text Solution

    |