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Lights of two different frequencies whose photons have energies 1 and 2.5 eV, respectively, successively illuminate a metal whose work function is 0.5 eV. The ratio of the maximum speeds of the emitted electrons

A

`1 : 2`

B

`3 : 1`

C

`1 : sqrt(2)`

D

`2 : 1`

Text Solution

Verified by Experts

The correct Answer is:
`3`
`(KE_(1))/(KE_(2))=(hf_(1)-w_(0))/(hf_(2)-w_(0))=(1)/(2)rArr(V_(1))/(V_(2))=(1)/(sqrt(2))`
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NARAYNA-DUAL NATURE OF RADIATION AND MATTER-EXERCISE - 1 (C.W)
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