Two photons of energies twice and thrice...

Two photons of energies twice and thrice the work function of a metal are incident on the metal surface .Then, the ratio of maximum velocities of the photoelectrons emitted in the two cases respectively ,is

`sqrt(2) : 1`

`sqrt(3) : 1`

`sqrt(3) : sqrt(2)`

`1 : sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:

`(V_(1))/(V_(2))=sqrt((E_(1)-W_(0))/(E_(2)-W_(0)))`

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