An electron and a photon have same wavelength of `10^(-9)` m. If E is the energy of the photon and p is the momentum of the electron, the magnitude of E/p in SI units is

Options

A. `3.33 xx 10^(-9)`
B. `3.0 xx 10^(8)`
C. `1.1 xx 10^(-19)`
D. `9 xx 10^(16)`

Answer

2

Explanation

For electron, `p(h)/(lambda)`l and for photon , `E = (hc)/(lambda).`
`therefore " " (E)/(P)=(hc//lambda)/(h//lambda)=c=3xx10^(8).`