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The ratio of wavelength of deutron and p...

The ratio of wavelength of deutron and proton accelerated through the same potential difference will be -

A

`1 :2`

B

`2 :1`

C

`sqrt(2) : 1`

D

`1 : sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
3
`lambda=(h)/(sqrt(2qVm))orlambdaprop(1)/(sqrt(m))`
`therefore " " (lambda_(p))/(lambda_(d))=sqrt((m_(d))/(lambda_p))=sqrt(2).`
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NARAYNA-DUAL NATURE OF RADIATION AND MATTER-EXERCISE - 1 (C.W)
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