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The de Broglie wavelength of an electron...

The de Broglie wavelength of an electron accelerated by an electric field of V volt is given by:

A

`sqrt((150)/(V) A`

B

`(h)/(sqrt(2mE)A`

C

`(h)/(sqrt(2mKT)A`

D

`sqrt((12.26)/(V)A`

Text Solution

Verified by Experts

The correct Answer is:
1

`lambda = (p)/(h) = (h)/(mv)`
also `KE = (1)/(2) mv^(2) xx (m)/(m)`
`2(KE) **m=p^(2)`
` p = sqrt(2(KE)m)`
`p= sqrt(2(eV)m)`
lambda = (h)/sqrqt(2meV)`
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