A particle is moving three times as fast as an electron. The ratio of the de- Broglie wavelength of the particle to that of the electron is `1.813xx10^-4`. Calculate the particle's mass and identify the particle. Mass of electron `=9.11xx10^(-31)kg`.

Options

A. `1.275 xx 10^(-26) kg`, Neutron
B. `1.576 xx 10^(-27)` kg, Proton
C. `1.765 xx 10^(-25) kg`, Electron
D. `1.675 xx 10^(-27)kg,` Neutron

Answer

4

Explanation

`(lambda_(p))/(lambda_(e))=((h)/(m_(p)v_(p)))/((h)/(m_(e)v_(e)))=(m_(e)v_(e))/(m_(p)v_(p))`
`1.813xx10^(-4)=(1.91xx10^(-31))/(m_(p))xx(1)/(3)`
`rArr m_(p) = 1.675xx10^(-27)kg`
Therefore particle is neutron.