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U.V. light of wavelength 800A^(@)&700A^(...

`U.V`. light of wavelength `800A^(@)&700A^(@)` falls on hydrogen atoms in their ground state `&` liberates electrons with kinetic energy `1.8eV` and `4eV` respectively. Calculate planck's constant.

A

`6.57 xx 10^(-34) js`

B

`6.63 xx 10^(-34) js`

C

`6.66 xx 10^(-34) js`

D

`6.77 xx 10^(-34) js`

Text Solution

Verified by Experts

The correct Answer is:
1
`(hc)/(lambda)=w+eV_(0)`
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NARAYNA-DUAL NATURE OF RADIATION AND MATTER-EXERCISE - 2 (H.W)
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  2. Light rays of wavelength 6000A^(@) and of photon intensity 39.6Wm^-2 i...

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  3. Ligth of wavelength 4000A^(@) is incident on a metal surface of work f...

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  4. A photomental is illuminated by lights of wavelenght lambda(1) and lam...

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  10. Photons of energy 2.0eV fall on a metal plate and release photoelectro...

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  20. If the uncertainity in the position of an electron is 10^(-10) m, then...

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