The electric field associated with a light wave is given by `E=E_(0)sin[(1.57xx10^(7)m^(-1))(ct-x)]`. Find the stopping potential when this light is used in an experiment on a photoelectric effect with the emitter having work function 2.1eV. `h=6.62xx10^(-34)Js`.

Options

A. 1.2 V
B. 1.1 V
C. 2 volt
D. 2.1 V

Explanation

`E=(6.62xx10^(-34)xx0.75xx10^(15))/(1.6xx10^(-19))eV=3.1eV`
`eV_(0)=E-w,V_(0)=1.2V`