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The classical method of a hydrogen atom ...

The classical method of a hydrogen atom in its normal, unexcited configuration has an electron that revolves around a proton at a distance of `5.3 xx 10^(11)m`.
(a) What is the electric potential due to the proton at the position of electron ?
(b) Determine the electrostatic potential energy between the two particles.

Text Solution

Verified by Experts

The electric potential `V_(p)` due to the proton can be found by using `V = (kQ)/( r) ` and we can subsequently find the electrostatic potential energy by using `U = (-e) V_(P)` where - e is the electron charge.
(a) `V_(P)=(+theta)/(4pi_(0)r)=((9.0xx10^(9)N.m^(2)IC^(2))(1.6xx10^(-19)))/(5.3xx10^(-11)m)=27 V`
(b) `U = (-e)V_(P)=(-1.6xx10^(-19)C)(27V)`
`=-4.3xx10^(-18)`J .
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