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A bullet of mass 2 gm is having a charge...

A bullet of mass `2 gm` is having a charge of `2 muc`. Through what potential difference must it be accelerated, starting from rest, to acquire a speed of `10 m//s`

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Use the relation qV = `(1)/(2) mv^(2), ` Here, q = 2 ` xx 10^(-6)` coulomb , m = 2 `xx 10^(-3)` kg, v = 10 m/s
therefore V = `(mv^(2))/(2q) = (2xx 10^(-3) (10)^(2))/(2 xx 2xx 10^(-6)) = (10^(-1))/(2 xx10^(-6)) = 5 xx 10^(4) `volt = 50 kV
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