A charge Q has been divided on two concentirc conducting spheres of radii `R_(1) and R_(2) (R_(1) gt R_(2))` such that the surface charge
densities on both the sphere is same.
Find the potential at their common center.

Explanation

To find the potential at the common center of two concentric conducting spheres with the same surface charge density, we can follow these steps:

### Step 1: Understand the Relationship Between Charges
Given that the surface charge densities on both spheres are the same, we can express this mathematically. The surface charge density (σ) is given by:

\[ \sigma = \frac{q_1}{4\pi R_1^2} = \frac{q_2}{4\pi R_2^2} \]
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