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A parallel -plate capacitor is connected...

A parallel -plate capacitor is connected to a battery that maintains a constant potential difference V between the plates. If the plates are pulled away from each other, increasing their separation, does the magnitude of the charge on the plates (a) increase, (b) decrease, or (c ) remain the same ?

Text Solution

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Since the capacitance is given by `C=(epsilon_(0)A)/(d)` increasing the separation d decreases the capacitance . With a smaller value of C and a constant value for V the charge Q = CV will decrease.
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