The distance between the plates of a parallel plate capacitor is 3 mm the potential difference applied is `3xx10^(5)` V. If an electron travels from one plate to another the change in its potential energy is

Options

A. `3xx10^(5)` eV
B. 900 eV
C. `10^(8)` eV
D. Negligible

Explanation

To find the change in potential energy of an electron traveling between the plates of a parallel plate capacitor, we can follow these steps:

### Step 1: Identify the given values
- Distance between the plates, \( d = 3 \, \text{mm} = 3 \times 10^{-3} \, \text{m} \)
- Potential difference, \( \Delta V = 3 \times 10^{5} \, \text{V} \)
- Charge of an electron, \( e = 1.6 \times 10^{-19} \, \text{C} \)

### Step 2: Write the formula for change in potential energy
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