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Consider two capacitors : C(1) = 10 mu ...

Consider two capacitors `: C_(1) = 10 mu C` and `C_(2) = 40 mu F`. What is the equivalent capacitance if the two are connected.
(1) in parallel ?
(2) in series ?
(3) If the two are connected in series to a 9.0 volt battery what are the charges `Q_(1)` and `Q_(2)` stored on the two capacitors ?

Text Solution

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(A) `C_(eq). = C_(1)+C_(2)=10+40=50muF`
(b) `C_(eq)=(C_(1)C_(2))/(C_(1)+C_(2))= (10xx40)/((10+40))=(400)/(50)=8 mu` F
(c ) Q= `C_(eq)V=8xx9=72 mu` C
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