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A parallel plate capacitor of capacity 5...

A parallel plate capacitor of capacity `5 mu F` and plate separation `6 cm` is connected to a `1V` battery and is charged. A dielectric of dielectric constant `4` and thickness `4 cm` is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is.

A

`2 mu` C

B

`3 mu` C

C

`5 mu ` C

D

`10 mu ` C

Text Solution

Verified by Experts

Answer (3)
New capacitance is `(epsilon_(0)A)/((d-t)+(t)/(K))=(5d)/((d-t)+(t)/(K))=10muF`
`because ` Old capacitance is `(epsilon_(0)A)/(d) = 5 mu` F
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