If `a = sqrt3, b = (1)/(2) (sqrt6 + sqrt2), and c = sqrt2`, then find `angle A`

Explanation

To find angle A in the triangle with given sides \( a = \sqrt{3} \), \( b = \frac{1}{2}(\sqrt{6} + \sqrt{2}) \), and \( c = \sqrt{2} \), we will use the cosine rule.

### Step-by-Step Solution:

1. **Write down the cosine rule formula**:
\[ \cos A = \frac{b^2 + c^2 - a^2}{2bc} \]
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