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If x/acostheta+y/bsintheta=1,x/asintheta...

If `x/acostheta+y/bsintheta=1,x/asintheta-y/bcostheta=1`, then eliminate `theta`.

Text Solution

Verified by Experts

The correct Answer is:
`x^2/a^2+y^2/b^2=2`
Squaring and adding, we have `x^2/a^2+y^2/b^2=2`
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