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Let P={theta:sintheta-costheta=sqrt2cost...

Let `P={theta:sintheta-costheta=sqrt2costheta}and Q={theta: sintheta+costheta=sqrt2sintheta}` be two sets. Then

A

`psubQ and Q-P=phi`

B

`QcancelsubP`

C

`PcancelsubQ`

D

P=Q

Text Solution

Verified by Experts

The correct Answer is:
D
In set P, `sintheta=(sqrt2+1)costheta`
`or tantheta=sqrt2+1`
In set Q, `(sqrt2-1)sintheta=costheta`
`or tan thetaa=1/(sqrt2-1)=sqrt2+1`
`rArr P=Q`
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