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(sinA+sin3A)/(cosA+cos3A)=tanalpha, (cos...

`(sinA+sin3A)/(cosA+cos3A)=tanalpha, (cosA-cos2A)/(sinA+sin2A)=tanbeta, (sinA+sin3A+sin5A+sin7A)/(cosA+cos3A+cos5A+cos7A)=tan gamma, (cosA-cos5A-cos9A+cos13A)/(sinA-sin5A+sin9A-sin13A)=tandelta`, then (a)`alpha=4beta` (b)`gamma=2alpha` (c)`gamma=delta` (d)none

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