A particle starts from the origin at `t=Os` with a velocity of `10.0 hatj m//s` and moves in the `xy`-plane with a constant acceleration of `(8hati+2hatj)m//s^(-2)`. What time is the `x`-coordinate of the particle `16m`?

A particle starts from the origin at t = 0 s with a velocity of 10.0 hatj m//s and moves in the x-y plane with a constant acceleration of (8.0hati + 2.0hatj) m s^-2 ,:- At what time is the x- coordinate of the particle 16 m? What is the y-coordinate of the particle at that time?

A particle starts from the origin at f = 0 s with a velocity of 10.0 hatj m//s and moves in the x-y plane with a constant acceleration of (8.0 hat + 2.0 hatj) m s^-2 .

A particle starts from the origin at t= 0 s with a velocity of 10.0 hatj m//s and moves in the xy -plane with a constant acceleration of (8hati+2hatj)m//s^(-2) . Then y -coordinate of the particle in 2 sec is

A particle starts from the origin at t=0 with a velocity of 10.0 hat j m//s and moves in the x-y plane with a constant acceleration of ( 8.0 hat i + 2. 0 hat j ) ms^(-2) . (a) At what time is the x-coordinate of the particle 16 m ? What is the y-coordinate of the particle at that time ? (b) What is the speed of the particle at that time ?

A particle starts from the origin at t=0 with a velocity of 10.0 hat j m//s and moves in the X-y plane with a constant accleration of ( 8.0 hat I + 2. 0 hat j ) ms^(-2) . (a) At wht time is the x-coordinate of the particle 16 m ? What is the y-coordinate of the particle at that time ? ( b) What is the speed of the particle at that time ?