The angle bisectors of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Show that the bisectors of angles of a parallelogram form a rectangle.

Three statements are given below: I. In a ||gm, the angle bisectors of two adjacent angles enclose a right angle. I. The angle bisectors of a ||gm form a rectangle. III. The triangle formed by joining the midpoints of the sides of an isosceles triangle is not necessarily an isosceles triangle. Which is true?

In the alongside diagram, the bisectors of interior angles of the parallelogram PQRS enclose a quadrilateral ABCD. Show that: (i) anglePSB+angleSPB=90^(@) (ii) anglePBS=90^(@) (iii) angleABC=90^(@) (iv) angleADC=90^(@) (v) angleA=90^(@) (vi) ABCD is a rectangle thus, the bisectors of the angles of a parallelogram enclose a rectangle.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.

Prove that the quadrilateral formed by the bisectors of the angles of a parallelogram is a rectangle.