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Find the values of `alpha` lying between 0 and `pi` for which of the inequality: `tanalpha gt tan^(3) alpha` is valid.

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We have : `tanalpha-tan^(3)alpha gt 0 rArr tanalpha(1-tan^(2)alpha) lt 0`
So, `tanalpha lt -1,0 gt tan alpha gt 1`
`therefore` (Given inequality holds for) `alpha in (0,pi/4) cup (pi/2, (3pi)/4)`
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