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If the set of all values of `x` in `(-pi/2,pi/2)` satisfying `|4sinx+sqrt(2\ )+|

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`|4sinx+sqrt(2)| lt sqrt(6)`
`rArr -sqrt(6) lt 4sinx + sqrt(2) lt sqrt(6) rArr -sqrt(6) - sqrt(2) lt 4sinx lt sqrt(6) -sqrt(2)`
`rArr (-sqrt(6)+sqrt(2))/4 lt sinx lt (sqrt(6)-sqrt(2))/4 rArr -sqrt(6)- sqrt(2) lt 4sin x lt sqrt(6) - sqrt(2)`
`rArr -(sqrt(6) + sqrt(2))/4 lt sinx lt (sqrt(6)-sqrt(2))/(4) rArr -(5pi)/(12) lt x lt pi/12` for `x in (-pi/2, pi/2)`
Comparing with `(api)/(24) lt x lt (bpi)/24`, we get `a=-10, b=2`
`|(a-b)/3|=|(-10-2)/(3)|=4`
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