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If tanalpha=(1+2^(-x))^(-1), tanbeta=(1+...

If `tanalpha=(1+2^(-x))^(-1), tanbeta=(1+2^(x+1))^(-1)`, then `alpha+beta=`

A

`pi//6`

B

`pi//4`

C

`pi//3`

D

`pi//2`

Text Solution

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The correct Answer is:
B
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