Home
Class 11
PHYSICS
The area of a circle is given by A= pi r...

The area of a circle is given by `A= pi r^(2)`, where r is the radius. Calculate the rate of increase of area w.r.t radius.

Text Solution

Verified by Experts

The correct Answer is:
`2 pi r`

A `= pi r^(2)`
`(dA)/(dr)= (d)/(dr) (pir^(2)) = 2pir `
Promotional Banner

Topper's Solved these Questions

  • BASIC MATHEMATICS USED IN PHYSICS &VECTORS

    ALLEN|Exercise BEGINNER S BOX 4|1 Videos
  • BASIC MATHEMATICS USED IN PHYSICS &VECTORS

    ALLEN|Exercise BEGINNER S BOX 5|1 Videos
  • BASIC MATHEMATICS USED IN PHYSICS &VECTORS

    ALLEN|Exercise BEGINNER S BOX 2|3 Videos
  • CENTRE OF MASS

    ALLEN|Exercise EXERCISE-V B|19 Videos

Similar Questions

Explore conceptually related problems

The area of a circle is given by A=pir^(2) , where r is the radius . Calculate the rate of increases of area w.r.t. radius.

The volume of sphere is given by V=(4)/(3) pi R^(3) where R is the radius of sphere. Find the rate of change of volume with respect to R.

The diameter of a circle is increasing at the rate of 1 cm/sec. When its radius is pi , the rate of increase of its area, is

The area of the reactangle polygen of n sides is (where R is the radius of the circumpolygon)

If the rate of increase of the radius of a circle is 5 cm/sec, then the rate of increase of its area, when the radius is 20 cm, will be

What is the area of a regular hexagon inscribed in a circle of radius r ?

The side of a square is increasing at ther rate of 0.2 cm//s . The rate of increase of perimeter w.r.t. time is :

The side of a square is increasing at the rate of 0.2 cm/s. The rate of increase of perimeter w.r.t time is :

If the area of a circle changes at the rate of 2pi cm^(2)//sec , then, when the radius is 10cm, the radius is changing at the rate of