Find the vector components of `veca= 2hati+ 3hatj` along the directions of `hati+hatj`.

Answer

`(5)/(2) (hati+hatj)`

Explanation

Vector component of `veca` in the direction of `vecb(hati+hatj)`
`" "=(acos theta ) vecb= ((abcos theta )/(b))(vecb)/(b) = (veca*vecb)/(|vecb|^(2))vecb`
`= ((2hati+3hatj)*(hati+hatj))/([sqrt(1^(2)+1^(2))]^(2))(hati+hatj)`
`= (2xx1+3xx1)/(2) (hati+hatj)= (5)/(2) (hati+hatj)`