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A particle moves along the straight line...

A particle moves along the straight line `y= 3x+5`. Which coordinate changes at a faster rate ?

A

x- coordinate

B

y- coordinate

C

Both x and y coordinates

D

Data insufficient

Text Solution

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The correct Answer is:
To determine which coordinate changes at a faster rate for a particle moving along the straight line given by the equation \( y = 3x + 5 \), we can follow these steps: ### Step 1: Understand the relationship between x and y The equation \( y = 3x + 5 \) shows that y is a linear function of x. The slope of the line is 3, which indicates how y changes with respect to x. ### Step 2: Differentiate the equation with respect to time To find how the coordinates change with respect to time, we differentiate both sides of the equation with respect to time \( t \): \[ \frac{dy}{dt} = \frac{d}{dt}(3x + 5) \] ### Step 3: Apply the chain rule Using the chain rule, we differentiate the right-hand side: \[ \frac{dy}{dt} = 3 \frac{dx}{dt} + 0 \] The derivative of the constant (5) is zero. ### Step 4: Simplify the equation This simplifies to: \[ \frac{dy}{dt} = 3 \frac{dx}{dt} \] ### Step 5: Compare the rates of change From the equation \( \frac{dy}{dt} = 3 \frac{dx}{dt} \), we can see that the rate of change of y with respect to time is three times the rate of change of x with respect to time. This indicates that y changes at a faster rate than x. ### Conclusion Thus, the y-coordinate changes at a faster rate than the x-coordinate. ### Final Answer The y-coordinate changes at a faster rate. ---

To determine which coordinate changes at a faster rate for a particle moving along the straight line given by the equation \( y = 3x + 5 \), we can follow these steps: ### Step 1: Understand the relationship between x and y The equation \( y = 3x + 5 \) shows that y is a linear function of x. The slope of the line is 3, which indicates how y changes with respect to x. ### Step 2: Differentiate the equation with respect to time To find how the coordinates change with respect to time, we differentiate both sides of the equation with respect to time \( t \): ...
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