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Given that A=B. What is the angle betwee...

Given that `A=B`. What is the angle between `(vecA+vecB) and (vecA-vecB)` ?

A

`30^(@) `

B

`60^(@)`

C

`90^(@)`

D

`180^(@)`

Text Solution

Verified by Experts

The correct Answer is:
3
`cos theta = (vecP*vecQ)/(|vecP||vecQ|) = ((vecA+vecB)*(vecA-vecB))/(|vecA+vecB||vecA-vecB|)`
`= (A^(2)-B^(2))/(|vecA+vecB||vecA-vecB|) = 0 rArr theta = 90^(@)`
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