A magnitude of vector `vecA,vecB` and `vecC` are respectively `12, 5` and `13` units and `vecA+vecB=vecC` then the angle between `vecA` and `vecB` is

Options

A. 0
B. `pi//3`
C. `pi//2`
D. `pi//4`

Answer

C

Explanation

`vecA+vecB = vecC rArr A^(2) +B^(2) = C^(2)`
thus angle between `vecA and vecB ` is `90^(@)`.