Home
Class 11
PHYSICS
If velocity of a particle is given by v=...

If velocity of a particle is given by `v=(2t+3)m//s`. Then average velocity in interval `0letle1` s is :

A

`(7)/(2) m//s `

B

`(9)/(2) m//s `

C

`4 m//s`

D

`5 m//s`

Text Solution

Verified by Experts

The correct Answer is:
3

`v_("av")= (intvdt)/(intdt) = (overset(1)underset(0) int (2t+ 3) dt)/( overset1 underset0 int dt) = ((t^(2) + 3t)_(0)^(1))/((t)_(0)^(1))= 4m//s `
Promotional Banner

Topper's Solved these Questions

  • BASIC MATHEMATICS USED IN PHYSICS &VECTORS

    ALLEN|Exercise EXERCISE-IV ASSERTION & REASON|11 Videos
  • BASIC MATHEMATICS USED IN PHYSICS &VECTORS

    ALLEN|Exercise EXERCISE-II AIPMT/NEET & AIIMS (2006- 2018)|6 Videos
  • CENTRE OF MASS

    ALLEN|Exercise EXERCISE-V B|19 Videos

Similar Questions

Explore conceptually related problems

Velocity of a particle is given as v = (2t^(2) - 3)m//s . The acceleration of particle at t = 3s will be :

A particle moves in a straight line. Its position ( in m) as function of time is given by x = (at^2 + b) What is the average velocity in time interval t = 3s to t = 5s in ms^(-1) . (where a and b are constants and a = 1ms^(-2), b = 1m ).

If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

. If the velocity of a particle is (10 + 2 t 2) m/s , then the average acceleration of the particle between 2s and 5s is

If the velocity of a particle is (10+2t^(2)m/s ,then the average acceleration of the particle between 2s and 5s is (in m/s^2)

The velocity of a particle is given by vec(v) = 2hat(i)-hat(j)+2hat(k) in m//s for time interval t = 0 to t = 10 sec. If the distance travelled by the particle in given time interval 10n , find value of n is.

The position of a particle moving on the x-axis is given by x=t^(3)+4t^(2)-2t+5 where x is in meter and t is in seconds (i) the velocity of the particle at t=4 s is 78 m//s (ii) the acceleration of the particle at t=4 s is 32 m//s^(2) (iii) the average velocity during the interval t=0 to t=4 s is 30 m//s (iv) the average acceleration during the interval t=0 to t=4 s is 20 m//s^(2)

Five particles have speeds 1, 2, 3, 4, 5 m/s. The average velocity of the particles is (in m/s)

The velocity of a particle is given by v=(2t^(2)-3t+10)ms^(-1) . Find the instantaneous acceleration at t = 5 s.

A particle moves in a straight line with uniform acceleration. Its velocity at time t=0 is v_1 and at time t=t is v_2. The average velocity of the particle in this time interval is (v_1 + v_2)/2 . Is this statement true or false?