Taking foce, length and time to be the fundamental quantities find the dimension of
a. density, b. pressure,
c. momentum and d. energy

Answer

(a) `[M^(0)L^(0)T^(0)K^(1)]`
(b) `[ML^(2) T^(-2)]`
(c ) `[ML^(-1)T^(-2)]`
(d) `[M^(0)L^(0)T^(-1)]`

Explanation

(a) [Temperature] = [K]
(b) KE = `(1)/(2) mv^(2)`
`rArr [KE] = [m] [v]^(2) = M(LT^(-1))^(2) = [ML^(2)T^(-2]`
(c ) P `= (F)/(A) rArr [P] = ([F]) /( [A]) = (MLT^(-2)) /(L^(2)) = [ML^(-1)T^(-2)]`
(d) `omega = (v)/(r ) rArr [omega] = ([v]) /([r]) = (LT^(-1))/(L) = [T^(-1)]`