The dimensional formula for Planck's constant and gravitational constant G respectively are :-

Options

A. `[ML^(3)T^(-2)], [M^(-1)L^(2)T^(-3)]`
B. `[ML^(2)T^(-1)], [M^(-1)L^(3)T^(-2)]`
C. `[ML^(3)T^(-2)], [M^(-1)L^(2)T^(2)]`
D. `[MLT^(-3)], [M^(-1)L^(3)T^(-3)]`

Answer

B

Explanation

Planck's constant h = `("Energy")/("Frequency")`
`h= ([ML^(2)T^(-2)])/([T^(-1)]) = [ ML^(2)T^(-1)]`
`F = (Gm_1m_2)/(r^(2)) therefore ` Gravitational constant `G= (Fr^(2))/(m_1m_2)`
`[G] = ([M^(1)L^(1)T^(-2)][L^(2)])/([M^(2)])= [M^(-1)L^(3)T^(-2)]`