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In a vernier callipers, one main scale d...

In a vernier callipers, one main scale division is x cm and n divisions of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is :-

A

`((n-1)/(n))x`

B

`(nx)/((n-1))`

C

`(x)/(n) `

D

`(x)/((n-1))`

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The correct Answer is:
To find the least count of a vernier caliper given that one main scale division is \( x \) cm and \( n \) divisions of the vernier scale coincide with \( (n-1) \) divisions of the main scale, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - The least count (LC) of a measuring instrument is the smallest value that can be measured accurately using that instrument. - The formula for least count is given by: \[ \text{Least Count} = \text{Value of 1 Main Scale Division (MSD)} - \text{Value of 1 Vernier Scale Division (VSD)} \] 2. **Identify the Values**: - We know that 1 Main Scale Division (MSD) = \( x \) cm. - We also know that \( n \) divisions of the vernier scale coincide with \( (n-1) \) divisions of the main scale. 3. **Calculate the Value of 1 Vernier Scale Division (VSD)**: - Since \( n \) divisions of the vernier scale coincide with \( (n-1) \) divisions of the main scale, we can express this relationship mathematically: \[ n \times \text{VSD} = (n-1) \times \text{MSD} \] - Substituting the value of MSD: \[ n \times \text{VSD} = (n-1) \times x \] - Now, solving for VSD: \[ \text{VSD} = \frac{(n-1) \times x}{n} \] 4. **Substitute VSD into the Least Count Formula**: - Now we can substitute the value of VSD into the least count formula: \[ \text{Least Count} = x - \text{VSD} \] - Substituting for VSD: \[ \text{Least Count} = x - \frac{(n-1) \times x}{n} \] 5. **Simplify the Expression**: - To simplify, we can factor out \( x \): \[ \text{Least Count} = x \left(1 - \frac{(n-1)}{n}\right) \] - This simplifies to: \[ \text{Least Count} = x \left(\frac{n - (n-1)}{n}\right) = x \left(\frac{1}{n}\right) \] - Therefore, the least count is: \[ \text{Least Count} = \frac{x}{n} \text{ cm} \] ### Final Answer: The least count of the vernier calipers is \( \frac{x}{n} \) cm.

To find the least count of a vernier caliper given that one main scale division is \( x \) cm and \( n \) divisions of the vernier scale coincide with \( (n-1) \) divisions of the main scale, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definitions**: - The least count (LC) of a measuring instrument is the smallest value that can be measured accurately using that instrument. - The formula for least count is given by: \[ ...
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Knowledge Check

  • In a vernier callipers, one main scale division is x cm and n division of the vernier scale coincide with (n-1) divisions of the main scale. The least count (in cm) of the callipers is:

    A
    `((n - 1)/(n))x `
    B
    `((nx)/(n - 1))`
    C
    `x/n`
    D
    `(x/(n - 1))`
  • The main scale of a vernier callipers has n divisions/cm. n divisions of the vernier scale coincide with (n-1) divisions of main scale. The least count of the vernier callipers is,

    A
    `(1)/(n(n+1))cm`
    B
    `(1)/((n+1)(n-1))cm`
    C
    `(1)/(n)cm`
    D
    `(1)/(n^2)cm`
  • One centimetre on the main scale of vernier callipers is divided into ten equal parts. If 10 divisions of vernier scale coincide with 8 small divisions of the main scale, the least count of the callipers is

    A
    0.01 cm
    B
    0.02 cm
    C
    0.05 cm
    D
    0.005 cm
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