Home
Class 12
MATHS
Let alpha=som^(-1)((36)/(85)),beta=cos^(...

Let `alpha=som^(-1)((36)/(85)),beta=cos^(-1)(4/5)a n dgamma=tan^(-1)(8/(15))` then `cotalpha+cotbeta+cotgamma=cotalphacotbetacotgamma` `tanalphatanbeta+tanbetatangamma+tanalphatangamma=1` `tanalpha+tanbeta+tangamma=tanalphatanbetatangamma` `cotalphacotbeta+cotbetacotgamma+cotalphacotgamma=1`

Promotional Banner

Similar Questions

Explore conceptually related problems

Let alpha=sin^(-1)(36/85), beta=cos^(-1)(4/5) and gamma=tan^(-1)(8/15) then

Let alpha=som^(-1)((36)/(85)),beta=cos^(-1)((4)/(5)) and gamma=tan^(-1)((8)/(15)) then cot alpha+cot beta+cot gamma=cot alpha cot beta cot gammatan alpha tan beta+tan beta tan gamma+tan alpha tan gamma=1tan alpha+tan beta+tan gamma=tan alpha tan beta tan gammacot alpha cot beta+cot beta cot gamma+cot alpha cot gamma=1

Let alpha = sin^(-1) ((36)/(85)), beta = cos^(-1) ((4)/(5)) and gamma = tan^(-1) ((8)/(15)) Then

If alphagt0, betagt0, gammagt0 and alpha+beta+gamma lt pi/2 show that tanalphatanbeta+tanbetatangamma+tangammatanalphalt1

If alphagt0, betagt0, gammagt0 and alpha+beta+gamma lt pi/2 show that tanalphatanbeta+tanbetatangamma+tangammatanalphalt1

Let alpha,betaa n dgamma be some angles in the first quadrant satisfying tan(alpha+beta)=(15)/8a n dcos e cgamma=(17)/8, then which of the following hold(s) good? alpha+beta+gamma=pi cotalpha+tanbeta+tangamma=tanalphatanbetatangamma tanalpha+tanbeta+tangamma=tanalphatanbetatangamma tanalphatanbeta+tanbetatangamma+tangammatanalpha=1

Let alpha,betaa n dgamma be some angles in the first quadrant satisfying tan(alpha+beta)=(15)/8a n dcos e cgamma=(17)/8, then which of the following hold(s) good? (a) alpha+beta+gamma=pi (b)cotalpha+tanbeta+tangamma=tanalphatanbetatangamma (c)tanalpha+tanbeta+tangamma=tanalphatanbetatangamma (d)tanalphatanbeta+tanbetatangamma+tangammatanalpha=1

Prove that tan(alpha-beta)=(tanalpha-tanbeta)/(1+tanalphatanbeta)

Prove that tan(alpha+beta)=(tanalpha+tanbeta)/(1-tanalphatanbeta)

Show that tanalphatanbeta=tan^2gamma when tan(alpha-beta)/tanalpha+sin^2gamma/sin^2alpha=1