A screen is placed `2m` away from the single narrow slit. Calculate the slit width if the first minimum lies `5 mm` on either side of the central maximum. Incident plane waves have a wavelength of `5000 Å`.

A screen is placed 2 m away from a narrow slit.Find the sit width ,if the first minimum lies 5 mm on eighter side of the central maximum,when plane waves of 5 xx 10^(-7) m are incident on the slit.

For producing a fraunhofer diffraction fringe, a screen is placed 2m away from a single narrow slit. If the width of slit is 0.2 mm, it is found that first minimum lies 5 mm on either side of the central maximum. Find the wavelength of the incident light.

A screen is at a distance of 2m from a narrow slit illuminated with light of 600nm. The first minimum lies 5mm on either side of the central maximum. The width of slit is

A screen is placed 2 m away from a narrow slit. If the first minimum lies 5 mm from either side ofthe centre maxima, when plane waves of wavelength 5 xx 10^-7m are used, the slit width is

In Fraunhaffer diffraction by a narrow slit, a screen is placed, at a distance of 2 m, from the lens to obtain a diffraction pattern. If the slit width is 0.2 mm and the first minimum is 5 mm, on either side of the central maximum. Find the wavelength of light.

In Fraunhofer diffraction by a narrow slit, a screen is placed at a distance of 2m from the lens to obtain the diffration pattern. If the Slit width is 0.2mm and the first minimum is 5mm on either side of central maximum, find the wavelength of light.