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The expression ((1+tan3 7^(@))(1+tan8^(@...

The expression `((1+tan3 7^(@))(1+tan8^(@))(1+tan1 5^(@))(1+tan3 0^(@)))/((1+tan2^(@))(1+tan4 3^(@)))`reduces to

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The expression ((1+tan37^(@))(1+tan8^(@))(1+tan15^(@))(1+tan30^(@)))/((1+tan2^(@))(1+tan43^(@))) reduces to

(1+tan1^(0))(1+tan2^(0))(1+tan3^(0)).......(1+tan45^(0)) =?

Prove that (1 + tan 1^(@)) (1 + tan 2^(@)) (1 + tan 3^(@)) …. (1 + tan 44^(@)) is multiple of 4.

If (1+tan1^(@)) *(1+tan2^(@))*(1+tan3^(@)) …….(1+tan45^(@)) = 2^(n) , then 'n' is equal to :

If (1+tan1^(@)) *(1+tan2^(@))*(1+tan3^(@)) …….(1+tan45^(@)) = 2^(n) , then 'n' is equal to :

S o l v e(sin1 0^(@))^(tanx+tan3x)=tan1 5^(@)+tan3 0^(@)+tan1 5^(@)tan3 0^(@), x in (0,pi]

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1) (1/5) + tan^(-1) (1/7) + tan^(-1) (1/3) + tan^(-1) (1/8) = π/4