An alpha particle of energy 4MeV is scattered through an angle of `180^(@)` by a gold foil (Z=79). Calculate the maximum volume in which positive charge of the atom is likely to be concetrated?

An alpha -particle of energy 4 Me V is scattered by gold foil (Z = 79) .Calculate the maximum volume in which positive charge of the atom is likely to be concentrated.

alpha- particles of 6 MeV energy is scattered back form a silver foil. Calculate the maximum volume in which the entire positive charge fo the atom is supposed to be concentrated. ( Z for silver = 47 )

An alpha particle with Kinetic energy 0.27 MeV is deflected through an angle of 60^(@) by a golden foil. Find the corresponding value of the aiming parameter.

An alpha particle of energy 5 MeV is scattered through 180^(@) by a found uramiam nucleus . The distance of appreach is of the order of

An alpha particle of energy 5 MeV is scattered through 180^(@) by a fixed uranium nucleus. The distance of the closest approach is of the order of ........