`DeltaS=(q_(rev))/(T)`, so

Assertion:The SI unit of entropy is JK^(-1)mol^(-1) Reason: DeltaS=(q_(rev))/(T)

Explain change in entropy of a system during a reversible process Delta S = (q_(rev))/(T)

The entropy change can be calculated by using the expression, DeltaS=(q_("rev"))/(T) . When water freezes in a glass beaker, choose the correct statement amongst the following:

The entropy change can be calculated by using the expression DeltaS-(q_(rev))/(T) . When water freezes in a glass beaker, choose the correct statement amongst the following:

The entropy change can be calculated by using the expression DeltaS-(q_(rev))/(T) . When water freezes in a glass beaker, choose the correct statement amongst the following:

As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by Delta S = (Q_(rev))/(T) What is the change in entropy of the universe due to the following reaction occuring at 27^(@)C ? A + 2B rarr C + 2D, Delta H = +1.8 kJ mol^(-1) Molar entropy values of A, B, C and D are 1,2,3 and 4 JK^(-1) mol^(-1) respectively.