A compound on analysis gave the following percentage composition by weight: hydrogen = 9.09, oxygen = 36.36 carbon = 54.55
Its `VD` is 44. Find the molecular formula of the compound.

A compound on analysis gave the following percentage composition by mass: H = 9.09, O = 36.36, C = 54.55. Molecular mass of compound is 88. Find its molecular formula.

A compound (C_(x)H_(y)O_(z)) on analysis gave the following percentage composition by weight : Hydrogen = 9.09, Oxygen = 36.36, Carbon = 54.55 Its vapour denstiy is 44. What is the value of (y+z-x) ?

A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, 0 = 36.36%

A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, 0 = 36.36%

An organic compound on analysis gave the following percentage composition of C= 57.8, H= 3.6 and the rest is oxygen. Vapour density of the compound is 83. Find out the molecular formula of the compound.

A carbon compound on analysis gave the following percentage composition, carbon 14.5%, hydrogen 1.8%, chlorine 64.46%, oxygen 19.24%. Calculate the empirical formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.

A compound on analysis gave the following percentage composition C = 54.54%, H, 9.09% 0 = 36.36. The vapour density of the compound was found to be 44. Find out the molecular formula of the compound.