If `alpha` and `beta` are the solution of the equation `acos2theta+bsin2theta=c` then ` cos^2alpha+cos^2beta` is equal to

If alpha and beta are 2 distinct roots of equation a cos theta + b sin theta = C then cos( alpha + beta ) =

If alpha and beta are 2 distinct roots of equation a cos theta + b sin theta = C then cos( alpha + beta ) =

If alpha, beta are the solutions of a cos 2theta + b sin 2theta = c , then tan alpha tan beta=

If alpha, beta are the roots of the equation a cos theta + b sin theta = c , then prove that cos(alpha + beta) = (a^2 - b^2)/(a^2+b^2) .

If alpha and beta be two different roots of the equation acos theta + b sin theta = c then prove that cos(alpha +beta) =(a^(2)-b^(2))/(a^(2)+b^(2))

If alpha\ &\ beta satisfy the equation, a cos2theta+b sin2theta=c then prove that : cos^2alpha+cos^2beta=(a^2+a c+b^2)/(a^2+b^2)

If alpha and beta are the solutions of a cos theta+b sin theta=c , then prove that : cos (alpha- beta)= (2c^2- (a^2+b^2))/(a^2+b^2) .