Given mass number of gold `= 197`, Density of gold `= 19.7 g cm^(-1)`. The radious of the gold atom is appoximately:

Given mass number of gold = 197 , Density of gold = 19.7 g cm^(-3) . The radius of the gold atom is approximately:

Given mass number of gold = 197 , density of gold = 19.7 g cm^(-3) , Avogedro's number = 6 xx 10^(23) . The radius of the gold atom si approximately.

The density of gold is 19g//cm^(3) find the volume of 38 g

Find the mass of 1m^(3) of gold in kg when density of gold is 19 gcm^(-3)

Find thhe mass of 1 m^(3) of gold in kg when density of gold is 19 g cm^(-3) .

The density of gold is 19 g //cm^(2) . Find the volume of 95 g of gold.

Gold has cubic crystals whose unic cell has edge length of 407.9 pm. Density of gold is 19.3 g cm^(-3) . Calculate the number of atoms per unit cell. Also predict the type of crystal lattice of gold (Atomic mass of gold = 197 amu)

Gold has cubic crystals whose unic cell has edge length of 407.9 pm. Density of gold is 19.3 g cm^(-3) . Calculate the number of atoms per unit cell. Also predict the type of crystal lattice of gold (Atomic mass of gold = 197 amu)

Gold has cubic crystals whose unic cell has edge length of 407.9 pm. Density of gold is 19.3 g cm^(-3) . Calculate the number of atoms per unit cell. Also predict the type of crystal lattice of gold (Atomic mass of gold = 197 amu)