`x/3+4/3=2/3(4x-1)-(2x-(x+1)/3)`

If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?

((4x-3) / (2x + 1))-10 ((2x + 1) / (4x-3)) = 3, x! =-1/2, 3/4

Solve for x : (x-1)/(x-2)+(x-3)/(x-4)=3 1/3;\ \ x!=2,\ 4

Solve for :x:(x-1)/(x-2)+(x-3)/(x-4)=3(1)/(3),x!=2,4

Solve for x:(x-1)/(x-2)+(x-3)/(x-4)=3(1)/(3);x!=2,4

Simplify: (3x+2)(2x+3)-(4x-3)(2x-1)

Simplify: (3x+2)(2x+3)-(4x-3)(2x-1)

Without expanding, find the value of: (i) (x + 1)^4 - 4(x + 1)^3 (x - 1) + 6(x + 1)^2 (x - 1)^2 - 4(x + 1) (x - 1)^3 + (x -1)^4 (ii) (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4

Observe the following pattern (1x2)+(2x3)=(2x3x4)/(3)(1x2)+(2x3)+(3x4)=(3x4x5)/(3)(1x2)+(2x3)+(3x4)+(4x5)=(4x5x6)/(3) and find the of (1x2)+(2x3)+(3x4)+(4x5)+(5x6)