Home
Class 12
MATHS
The equation of normal to the curve y=6-...

The equation of normal to the curve `y=6-x^(2),` where the normal is parallel to the line `x-4y+3=0` is

Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of tangent to the curve y=6-x^(2) , where the normal is parallel to the line x-4y+3=0 is

Find the equation of the tangent to the curve y=6-x^(2) , where the normal is parallel to the line x-4y+3=0 .

The equation of normal to the curve x^(2)+y^(2)=5 , where the tangent is parallel to the line 2x-y+1=0 is

Find the equation of the normal to the curve : y=x^(3)+5x^(2)-10x+10, where the normal is parallel to the line x-2y+10=0.

Find the equation of normal to the curve : y = 5x^2 - 10x + 11 , where normal is parallel to the line x - 2y + 10 = 0

Find the equation of normal to the curve : y =x^3 - 7x^2 - 20x + 1 , where normal is parallel to the line x + 4y + 7 = 0

Find the equation of normal to the curve y = x^3 - 7x^2 -20x + 1 where normal is parallel to the line x + 4y + 7 = 0 .