`tan B + cot B=2sec 2A => A+B=`

tan B+cot B=2sec2A rArr A+B=

If tan A = 2 tan B + cot B, then 2 tan (A-B) is equal to

If sec A tan B+ tan A sec B=2 , sec A sec B +tan A tan B=k ,then k^(2) = (A) 2 (B) 5 (C) 4 (D) 1

Prove (tan A + cos ecB) ^ (2) - (cot B-sec A) ^ (2) = 2tan A cot B (cos ecA + sec B)

If 2 tan A + cot A = tan B , then cot A +2 tan (A-B)=

Show that (cot A + tan B) / (cot B + tan A) = cot A. tan B.

If tan A - tan B =x and cot B - cot A=y, then: cot(A-B)=

If tan A - tan B = x and cot A - cot B = y, then cot( A- B) =

If tan A - tan B = x and cot B - cot A= y, then cot (A-B) is

If A + B = 90^(@) , prove that sqrt((tan A tan B + tan A cot B)/(sin A sec B ) - (sin^(2) B)/(cos^(2)A)) = tan A .