calculate energy of one mole of photons of radiation whose frequency is `5xx10^(14) hz`

Explanation

Energy ( E ) of one photons
`E = hv`
`h=6.626 xx 10^(-34) Js`
`v=5 xx 10^(14) s^(-1) ("given")`
`E = (6.626 xx 10^(-34) Js ) xx (5 xx 10^(14) s^(-1))`
`= 3.313 xx 10^(-19) J`
Energy of one mole of photos
`=(3.313 xx 10^(-19) J) xx (6.022 xx 10^(23) mol^(-1))`
`199.51 kJ mol^(-1)`