The mass of an electron is `9.1 xx 10^(-25)J`, if its K.E. is `3.0 xx 10^(-25)J`. Calculate its wavelength.

Explanation

since `K.E = (1)/(2) mv^(2)`
`v = ((2K.E.)/(m) )=((2xx3.0 xx 10^(-25) kgm^(2) s^(-2))/(9.1 xx 10^(-31)))^(1/2)= 812 ms^(-1)`
`lambda= (h)/(mv)= (6.626 xx 108^(-34) js)/((9.1 xx 10^(-31) kg) (812 ms^(-1) ))`
`=8967 x 10^(-10) m = 896.7 nm`