Two particles A and B are in motion. If the wavelength associated with particle A is `5 xx 10^(-8)m`, calculate the wavelength associated with particle B if its momentum is half of A.

Explanation

we know , `lambda = (h)/(p)`
`(lambda_A)/(lambda_B) = (p_B)/(p_A) --------1 " "lambda_A = 5 xx 10^(-8) m,`
`p_B = (1)/(2) p_A,` i.e., `p_A = 2 p_B`
`therefore` from equal
`(5 xx 10^(-8) )/(lambda_B) = (p_B)/(2p_B)" "lambda_(B) = 10^(-7) m`