The kinetic energy of an electron is `4.55 xx 10^(-25)J`. Calculate the wavelength .
`[h = 6.6 xx 10^(-34)Js`, mass of electron `= 9.1 xx 10^(-31)kg]`

Explanation

`K. E = (1)/(2) mv^(2) = 4.55 xx 10^(-25) `
or `(1)/(2) xx 9.1 xx 10^(-31) xx v^2 = 4.55 xx 10^(-25)`
or `v^2 = (2xx 4.55 xx 10^(-25))/(9.1 xx 10^(-31 ) ) " "v=10^3 ms^(-1)`
Applying de Brogile equation
`lambda= (h)/(mv) = (6.6 xx 10^(-34) )/(9.1 xx 10^(-31) xx 10^(3)) = 0.72 xx 10^(-6) m`